*✅Top 10 Maths ques of ssc previous year paper* 1. *If the cost price of 20 articles is equal to the selling price of 15 articles, what is the profit percentage?* (A) 25% (B) 33.33% (C) 50% (D) 66.67% Answer: (C) 50% Explanation: Let the cost price (CP) of each article be ₹1. Therefore, CP of 20 articles = ₹20. Selling price (SP) of 15 articles = ₹20, so SP of each article = ₹20/15 = ₹4/3. Profit per article = SP - CP = ₹4/3 - ₹1 = ₹1/3. Profit percentage = (Profit/CP) × 100 = (1/3) × 100 = 33.33%. 2. *A train running at 60 km/h crosses a pole in 9 seconds. What is the length of the train?* (A) 120 meters (B) 150 meters (C) 180 meters (D) 200 meters Answer: (B) 150 meters Explanation: Speed = 60 km/h = 60 × (1000/3600) m/s = 50/3 m/s. Distance = Speed × Time = (50/3) × 9 = 150 meters. 3. *The ratio of the ages of A and B is 3:4. After 5 years, the ratio will be 4:5. What is the present age of A?* (A) 15 years (B) 20 years (C) 25 years (D) 30 years Answer: (A) 15 years Explanation: Let the present ages of A and B be 3x and 4x respectively. After 5 years, (3x + 5)/(4x + 5) = 4/5. Solving for x, we get x = 5. Therefore, A's age = 3x = 15 years. 4. *If the sum of the squares of two consecutive even numbers is 340, what are the numbers?* (A) 10 and 12 (B) 12 and 14 (C) 14 and 16 (D) 16 and 18 Answer: (C) 14 and 16 Explanation: Let the numbers be x and x + 2. Then, x² + (x + 2)² = 340. Solving for x, we get x = 14. Therefore, the numbers are 14 and 16. 5. *A man can row upstream at 6 km/h and downstream at 10 km/h. What is the speed of the current?* (A) 2 km/h (B) 3 km/h (C) 4 km/h (D) 5 km/h Answer: (A) 2 km/h Explanation: Speed of current = (Downstream speed - Upstream speed) / 2 = (10 - 6) / 2 = 2 km/h. 6. *The average of five consecutive odd numbers is 35. What is the smallest number?* (A) 27 (B) 29 (C) 31 (D) 33 Answer: (B) 29 Explanation: Let the numbers be x, x+2, x+4, x+6, x+8. Their average = (5x + 20)/5 = x + 4. Given, x + 4 = 35, so x = 31. Therefore, the smallest number is 31. 7. *If a + b = 12 and ab = 35, find the value of a² + b².* (A) 74 (B) 94 (C) 144 (D) 154 Answer: (A) 74 Explanation: a² + b² = (a + b)² - 2ab = 12² - 2×35 = 144 - 70 = 74. 8. *A sum of money amounts to ₹2,520 in 2 years at 5% per annum simple interest. What is the principal amount?* (A) ₹2,400 (B) ₹2,300 (C) ₹2,200 (D) ₹2,000 Answer: (D) ₹2,000 Explanation: Let the principal be P. Simple Interest (SI) = P × Rate × Time / 100 = P × 5 × 2 / 100 = 0.1P. Amount = Principal + SI = P + 0.1P = 1.1P. Given, 1.1P = 2,520, so P = 2,520 / 1.1 = ₹2,000. 9. *The perimeter of a rectangle is 60 meters, and its length is twice its breadth. What is the area of the rectangle?* (A) 100 m² (B) 180 m² (C) 200 m² (D) 220 m² Answer: (B) 200 m² Explanation: Let the breadth be x meters. Then, length = 2x meters. Perimeter = 2(length + breadth) = 60, so 2(2x + x) = 60, 6x = 60, x = 10. Therefore, length = 20 meters, breadth = 10 meters. Area = length × breadth = 20 × 10 = 200 m². 10. *If the difference between the compound interest and simple interest on a certain sum for 2 years at 10% per annum is ₹50, what is the sum?* (A) ₹5,000 (B) ₹4,500 (C) ₹4,000 (D) ₹3,500 Answer: (C) ₹5,000 Explanation: Difference between CI and SI for 2 years = P × (R/100)². Given, P × (10/100)² = 50, so P × 0.01 = 50, P = 50 / 0.01 = ₹5,000. https://whatsapp.com/channel/0029Vb4yZFxEquiTxKm3yJ0D/100